SQL Date Format Functions|Date Conversions| 2 digit month or day values

DATE FORMATS
Format #	Query (current date: 12/30/2006)	Sample
1	select convert(varchar, getdate(), 1)	12/30/06
2	select convert(varchar, getdate(), 2)	06.12.30
3	select convert(varchar, getdate(), 3)	30/12/06
4	select convert(varchar, getdate(), 4)	30.12.06
5	select convert(varchar, getdate(), 5)	30-12-06
6	select convert(varchar, getdate(), 6)	30 Dec 06
7	select convert(varchar, getdate(), 7)	Dec 30, 06
10	select convert(varchar, getdate(), 10)	12-30-06
11	select convert(varchar, getdate(), 11)	06/12/30
101	select convert(varchar, getdate(), 101)	12/30/2006
102	select convert(varchar, getdate(), 102)	2006.12.30
103	select convert(varchar, getdate(), 103)	30/12/2006
104	select convert(varchar, getdate(), 104)	30.12.2006
105	select convert(varchar, getdate(), 105)	30-12-2006
106	select convert(varchar, getdate(), 106)	30 Dec 2006
107	select convert(varchar, getdate(), 107)	Dec 30, 2006
110	select convert(varchar, getdate(), 110)	12-30-2006
111	select convert(varchar, getdate(), 111)	2006/12/30
TIME FORMATS
8 or 108	select convert(varchar, getdate(), 8)	00:38:54
9 or 109	select convert(varchar, getdate(), 9)	Dec 30 2006 12:38:54:840AM
14 or 114	select convert(varchar, getdate(), 14)	00:38:54:840

How to get 2 digit day or month format?
Solution: SELECT RIGHT('0' + RTRIM(MONTH(GETDATE())), 2);